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of the three circles (Figure 9). Offset each center point perpendicularly to the plane by a distance equal to the corresponding radius. The centers can be offset to either side of the plane. The three offset points define a single plane. In that plane we build three lines through each pair of points.
925:
identical circles. In the limit of two circles with the same radius but distinct centers moving to having the same center, the external center is the point at infinity corresponding to the slope of the line of centers, which can be anything, so no limit exists for all possible pairs of such circles.
924:
If the two circles are identical (same center, same radius), the internal center is their common center, but there is no well-defined external center – properly, the function from the parameter space of two circles in the plane to the external center has a non-removable discontinuity on the locus of
3227:
three given circles (Figure 11). By conjugate we imply that both tangent circles belong to the same family with respect to any one of the given pairs of circles. As we've already seen, the radical axis of any two tangent circles from the same family passes through the homothetic center of the two
917:
If the circles have the same center but different radii, both the external and internal coincide with the common center of the circles. This can be seen from the analytic formula, and is also the limit of the two homothetic centers as the centers of the two circles are varied until they coincide,
767:
More generally, taking both radii with the same sign (both positive or both negative) yields the inner center, while taking the radii with opposite signs (one positive and the other negative) yields the outer center. Note that the equation for the inner center is valid for any values (unless both
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relative to the circles are equal. The radical axis is always perpendicular to the line of centers, and if two circles intersect, their radical axis is the line joining their points of intersection. For three circles, three radical axes can be defined, one for each pair of circles
3255:. Given the three circles, the homothetic centers can be found and thus the radical axis of a pair of solution circles. Of course, there are infinitely many circles with the same radical axis, so additional work is done to find out exactly which two circles are the solution.
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Repeating the above procedure for different combinations of homothetic centers (in our method this is determined by the side to which we offset the centers of the circles) would yield a total of four lines — three homothetic centers on each line (Figure 10).
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Any pair of circles has two centers of similarity, therefore, three circles would have six centers of similarity, two for each distinct pair of given circles. Remarkably, these six points lie on four lines, three points on each line. Here is one way to show
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If we construct the tangent circles for every possible pair of antihomologous points we get two families of circles - one for each homothetic center. The family of circles of the external homothetic center is such that every tangent circle either contains
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Circles are geometrically similar to one another and mirror symmetric. Hence, a pair of circles has both types of homothetic centers, internal and external, unless the centers are equal or the radii are equal; these exceptional cases are treated after
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Conversely, if both radii are zero (two points) but the points are distinct, the external center can be defined as the point at infinity corresponding to the slope of the line of centers, but there is no well-defined internal center.
1875:{\displaystyle {\begin{aligned}&\triangle PIR\cong \triangle P'\!IR'\\&\implies \angle RPI=\angle IP'\!R'=\alpha \\&\implies \angle RS'\!Q'=\angle PP'\!R'=\alpha \quad {\text{(inscribed angle theorem)}}\end{aligned}}}
181:
to one another; in other words they must have the same angles at corresponding points and differ only in their relative scaling. The homothetic center and the two figures need not lie in the same plane; they can be related by a
193:. A clockwise angle in one figure would correspond to a counterclockwise angle in the other. Conversely, if the center is external, the two figures are directly similar to one another; their angles have the same sense.
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to be the point at infinity corresponding to the slope of this line. This is also the limit of the external center if the centers of the circles are fixed and the radii are varied until they are equal.
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of the centers of the circles, weighted by the opposite circle's radius – distance from center of circle to inner center is proportional to that radius, so weighting is proportional to the
2944:{\displaystyle {\frac {\overline {EP}}{\overline {EP'}}}={\frac {\overline {EQ}}{\overline {EQ'}}};\quad {\overline {EP}}\cdot {\overline {EQ'}}={\overline {EQ}}\cdot {\overline {EP'}}.}
189:
Homothetic centers may be external or internal. If the center is internal, the two geometric figures are scaled mirror images of one another; in technical language, they have opposite
956:. These four points lie on a circle that intersects the two given circles; the lines through the intersection points of the new circle with the two given circles must intersect at the
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to both circles (a bitangent line) passes through one of the homothetic centers, as it forms right angles with both the corresponding diameters, which are thus parallel; see
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If one radius is zero but the other is non-zero (a point and a circle), both the external and internal center coincide with the point (center of the radius zero circle).
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radii zero or one is the negative of the other), but the equation for the external center requires that the radii be different, otherwise it involves division by zero.
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of points which are common to two distinct and non-parallel planes is a line then necessarily these three points lie on such line. From the similarity of triangles
2117:, which is the line of points from which tangents to both circles have equal length. More generally, every point on the radical axis has the property that its
2209:
For each pair of antihomologous points of two circles exists a third circle which is tangent to the given ones and touches them at the antihomologous points.
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Any two pairs of antihomologous points can be used to find a point on the radical axis. Consider the two rays emanating from the external homothetic center
909:
are parallel to the line of centers (both for secant lines and the bitangent lines) and thus have no intersection. An external center can be defined in the
210:(Figure 3). Circles with radius zero can also be included (see exceptional cases), and negative radius can also be used, switching external and internal.
3228:
given circles. Since the tangent circles are common for all three pairs of given circles then their homothetic centers all belong to the radical axis of
571:
The external center can be computed by the same equation, but considering one of the radii as negative; either one yields the same equation, which is:
3199:(pink). Each pair of given circles has a homothetic center which belongs to the radical axis of the two tangent circles. Since the radical axis is a
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in the figure above. Conversely, if the circles fall on the same side of the line, it passes through the external homothetic center (not pictured).
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given circles or none (Figure 6). On the other hand, the circles from the other family always contain only one of the given circles (Figure 7).
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Figure 4: Lines through corresponding antihomologous points intersect on the radical axis of the two given circles (green and blue). The points
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In general, a line passing through a homothetic center intersects each of its circles in two places. Of these four points, two are said to be
102:
is an external homothetic center for the two triangles. The size of each figure is proportional to its distance from the homothetic center.
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holding the radii equal. There is no line of centers, however, and the synthetic construction fails as the two parallel lines coincide.
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drawn through corresponding endpoints of those radii, which are homologous points, intersect each other and the line of centers at the
1225:
1143:{\displaystyle \angle QES=\angle Q'\!ES',\quad {\frac {\overline {EQ}}{\overline {EQ'}}}={\frac {\overline {ES}}{\overline {ES'}}},}
2211:
The opposite is also true — every circle which is tangent to two other circles touches them at a pair of antihomologous points.
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in Figure 4. These rays intersect the two given circles (green and blue in Figure 4) in two pairs of antihomologous points,
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drawn through one endpoint and the opposite endpoint of its counterpart intersects each other and the line of centers at the
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To show this, consider two rays from the homothetic center, intersecting the given circles (Figure 8). Two tangent circles
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for the second ray. These four points lie on a single circle, that intersects both given circles. By definition, the line
17:
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If the two tangent circle touch collinear pairs of antihomologous point — as in Figure 5 — then because of the homothety
938:
999:
When two rays from the same homothetic center intersect the circles, each set of antihomologous points lie on a circle.
854:
for details. If the circles fall on opposite sides of the line, it passes through the internal homothetic center, as in
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Figure 9: In a three circle configuration, three homothetic centers (one for each pair of circles) lie on a single line
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exist which touch the given circles at the antihomologous points. As we've already shown these points lie on a circle
2559:{\displaystyle \angle O_{1}PQ=\angle O_{1}QP=\angle O_{2}P'\!Q'=\angle O_{2}Q'\!P'=\angle T_{1}QP'=\angle T_{1}P'\!Q.}
134:, the two figures are directly similar to one another; their angles have the same rotational sense. If the center is
79:
57:
50:
760:{\displaystyle (x_{e},y_{e})={\frac {-r_{2}}{r_{1}-r_{2}}}(x_{1},y_{1})+{\frac {r_{1}}{r_{1}-r_{2}}}(x_{2},y_{2}).}
564:{\displaystyle (x_{0},y_{0})={\frac {r_{2}}{r_{1}+r_{2}}}(x_{1},y_{1})+{\frac {r_{1}}{r_{1}+r_{2}}}(x_{2},y_{2}).}
206:. These two homothetic centers lie on the line joining the centers of the two given circles, which is called the
173:
The external (above) and internal (below) homothetic centers of the two circles (red) are shown as black points.
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Figure 5: Every circle which is tangent to two given circles touches them at a pair of antihomologous points
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If the circles have the same radius (but different centers), they have no external homothetic center in the
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All circles from a tangent family have a common radical center and it coincides with the homothetic center.
851:
286:
For a given pair of circles, the internal and external homothetic centers may be found in various ways. In
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is the radical axis of the new circle with the blue given circle. These two lines intersect at the point
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if radii drawn to them make the same angle with the line connecting the centers; for example, the points
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149:. The angles at corresponding points are the same and have the same sense; for example, the angles
44:
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Advanced
Euclidean Geometry: An Elementary treatise on the geometry of the Triangle and the Circle
944:
3284:
2197:, which is the radical center of the new circle and the two given circles. Therefore, the point
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1219:
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190:
138:, the two figures are scaled mirror images of one another; their angles have the opposite sense.
3179:
2099:{\displaystyle {\overline {IQ}}\cdot {\overline {IP'}}={\overline {IS}}\cdot {\overline {IR'}}.}
1996:{\displaystyle {\overline {IP}}\cdot {\overline {IQ'}}={\overline {IR}}\cdot {\overline {IS'}}.}
1676:{\displaystyle {\overline {EP}}\cdot {\overline {EQ'}}={\overline {ER}}\cdot {\overline {ES'}}.}
1573:{\displaystyle {\overline {EQ}}\cdot {\overline {EP'}}={\overline {ES}}\cdot {\overline {ER'}}.}
3289:
881:: in analytic geometry this results in division by zero, while in synthetic geometry the lines
61:
2752:. Then the intersecting point of the two radical axes must also belong to the radical axis of
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3252:
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Figure 10: All six homothetic centers (dots) of three circles lie on four lines (thick lines)
3120:{\displaystyle {\frac {\overline {H\!_{AB}B}}{\overline {H\!_{AB}A}}}={\frac {r_{B}}{r_{A}}}}
178:
123:
2170:. Tangents drawn from the radical center to the three circles would all have equal length.
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is in fact the homothetic center of the corresponding two circles. We can do the same for
8:
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in Figure 4. Points which are collinear with respect to the homothetic center but are
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1466:{\displaystyle \angle QSR'+\angle QP'\!R'=180^{\circ }-\alpha +\alpha =180^{\circ },}
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is the radical axis of the new circle with the green given circle, whereas the line
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910:
775:, two parallel diameters are drawn, one for each circle; these make the same angle
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Figure 8: The radical axis of tangent circles passes through the radical center
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BSHM Bulletin: Journal of the
British Society for the History of Mathematics
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2671:), as well as in the case of the internal homothetic center is analogous.
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964:
27:
Point from which two similar geometric figures can be scaled to each other
2166:); remarkably, these three radical axes intersect at a single point, the
145:
Figure 2: Two geometric figures related by an external homothetic center
3183:
Figure 11: The blue line is the radical axis of the two tangent circles
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is their external homothetic center. We construct an arbitrary ray from
222:
Figure 3: Two circles have both types of homothetic centers, internal (
169:
2686:
Figure 7: Family of tangent circles for the internal homothetic center
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Figure 6: Family of tangent circles for the external homothetic center
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with respect to the two tangent circles are equal which means that
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is the homothetic center. From that similarity, it follows that
994:
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177:
If two geometric figures possess a homothetic center, they are
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is also isosceles and a circle can be constructed with center
2204:
2653:{\displaystyle {\overline {T_{1}P'}}={\overline {T_{1}Q}}.}
937:"Homologous point" redirects here. Not to be confused with
3203:
this means that the three homothetic centers are collinear
2660:
This circle is tangent to the two given circles in points
2373:{\displaystyle {\overline {O_{1}P}}={\overline {O_{1}Q}}}
2201:
also lies on the radical axis of the two given circles.
1685:
The proof is similar for the internal homothetic center
2667:
The proof for the other pair of antihomologous points (
932:
2962:
2768:. This point of intersection is the homothetic center
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The lines pierce the plane of circles in the points
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1211:{\displaystyle \angle ESQ=\angle ES'\!Q'=\alpha .}
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3342:"The tangency problem of Apollonius: three looks"
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1358:{\displaystyle \angle QSR'=180^{\circ }-\alpha .}
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846:As a limiting case of this construction, a line
213:
1284:{\displaystyle \angle EP'\!R'=\angle ES'\!Q'.}
995:Pairs of antihomologous points lie on a circle
298:radius. Denoting the centers of the circles
2728:and thus the two rays are radical axes for
3330:
3223:be a conjugate pair of circles tangent to
1806:
1802:
1750:
1746:
811:homothetic center. Conversely, the lines
250:) from each homothetic center. The points
160:are both clockwise and equal in magnitude.
2205:Tangent circles and antihomologous points
80:Learn how and when to remove this message
3178:
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963:of the three circles, which lies on the
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290:, the internal homothetic center is the
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168:
140:
93:
43:This article includes a list of general
3138:are the radii of the circles) and thus
14:
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3339:
3175:Here is yet another way to prove this.
1580:In the same way, it can be shown that
3309:
2285:. It is easily proven that triangles
122:) is a point from which at least two
2246:which intersects the two circles in
933:Homologous and antihomologous points
779:with the line of centers. The lines
246:) are proportional to the distance (
29:
2963:Homothetic centers of three circles
939:Homologous points (computer vision)
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1584:can be inscribed in a circle and
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266:are homologous, as are the points
49:it lacks sufficient corresponding
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3244:e.g., they lie on a single line.
2222:Let our two circles have centers
2007:can be inscribed in a circle and
130:of one another. If the center is
872:
34:
3335:. New York: Dover Publications.
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1900:lie on a circle. Then from the
1888:is seen in the same angle from
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1063:
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3247:This property is exploited in
2109:Relation with the radical axis
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2959:belongs to the radical axis.
230:). The radii of the circles (
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852:tangent lines to two circles
214:Computing homothetic centers
186:from the homothetic center.
7:
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2308:are similar because of the
1902:intersecting chords theorem
952:are antihomologous, as are
362:and denoting the center by
10:
3412:
2966:
983:homologous are said to be
936:
196:
3361:10.1080/17498430601148911
3276:Homothetic transformation
1865:(inscribed angle theorem)
1015:They are similar because
967:of the two given circles.
126:figures can be seen as a
3320:--A Wolfram Web Resource
2276:until they intersect in
2181:for the first ray, and
1220:inscribed angle theorem
128:dilation or contraction
64:more precise citations.
3249:Joseph Diaz Gergonne's
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1473:which means it can be
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987:; for example, points
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3340:Kunkel, Paul (2007),
3313:Antihomologous Points
3271:Similarity (geometry)
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124:geometrically similar
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3310:Weisstein, Eric W.,
3251:general solution to
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2011:
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120:center of similitude
116:center of similarity
98:Figure 1: The point
18:Center of similitude
3331:Johnson RA (1960).
3290:Apollonius' problem
3253:Apollonius' problem
2951:Thus the powers of
2113:Two circles have a
1481:, it follows that
1002:Consider triangles
843:homothetic center.
346:and their radii by
3386:Euclidean geometry
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3396:Geometric centers
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1189:
1153:
1149:
1147:
1146:
1141:
1136:
1130:
1129:
1117:
1112:
1104:
1103:
1098:
1092:
1091:
1079:
1074:
1066:
1065:
1059:
1047:
1012:
990:
978:
962:
955:
951:
911:projective plane
908:
868:
838:
806:
778:
766:
764:
763:
758:
750:
749:
737:
736:
724:
722:
721:
720:
708:
707:
697:
696:
687:
679:
678:
666:
665:
653:
651:
650:
649:
637:
636:
626:
625:
624:
611:
603:
602:
590:
589:
570:
568:
567:
562:
554:
553:
541:
540:
528:
526:
525:
524:
512:
511:
501:
500:
491:
483:
482:
470:
469:
457:
455:
454:
453:
441:
440:
430:
429:
420:
412:
411:
399:
398:
379:
361:
345:
313:
292:weighted average
281:
265:
249:
245:
229:
226:) and external (
225:
204:general position
165:General polygons
159:
148:
101:
85:
78:
74:
71:
65:
60:this article by
51:inline citations
38:
37:
30:
21:
3411:
3410:
3406:
3405:
3404:
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3326:
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3235:
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3214:
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3109:
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3099:
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3093:
3071:
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3065:
3047:
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3033:
3032:
3027:
3019:
3013:
3006:
3002:
2998:
2994:
2975:
2971:
2969:Monge's theorem
2965:
2956:
2952:
2924:
2920:
2918:
2902:
2900:
2883:
2879:
2877:
2861:
2859:
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2707:
2668:
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2627:
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2602:
2598:
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2504:
2490:
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2475:
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2457:
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2438:
2420:
2416:
2398:
2394:
2389:
2386:
2385:
2355:
2351:
2350:
2348:
2330:
2326:
2325:
2323:
2321:
2318:
2317:
2303:
2293:
2286:
2283:
2277:
2271:
2261:
2255:
2251:
2247:
2243:
2239:
2236:
2229:
2223:
2210:
2207:
2198:
2194:
2190:
2186:
2182:
2178:
2174:
2164:
2157:
2150:
2143:
2136:
2129:
2123:
2111:
2079:
2075:
2073:
2057:
2055:
2038:
2034:
2032:
2016:
2014:
2012:
2009:
2008:
2004:
1976:
1972:
1970:
1954:
1952:
1935:
1931:
1929:
1913:
1911:
1909:
1906:
1905:
1897:
1893:
1889:
1884:
1883:
1869:
1868:
1863:
1848:
1839:
1822:
1813:
1796:
1795:
1781:
1772:
1740:
1739:
1731:
1719:
1696:
1694:
1691:
1690:
1686:
1656:
1652:
1650:
1634:
1632:
1615:
1611:
1609:
1593:
1591:
1589:
1586:
1585:
1581:
1553:
1549:
1547:
1531:
1529:
1512:
1508:
1506:
1490:
1488:
1486:
1483:
1482:
1454:
1450:
1429:
1425:
1414:
1405:
1388:
1377:
1374:
1373:
1369:
1340:
1336:
1325:
1314:
1311:
1310:
1303:
1292:
1270:
1261:
1244:
1235:
1227:
1224:
1223:
1191:
1182:
1159:
1156:
1155:
1151:
1122:
1118:
1105:
1102:
1084:
1080:
1067:
1064:
1052:
1040:
1020:
1017:
1016:
1014:
1003:
997:
988:
976:
960:
953:
949:
942:
935:
907:
901:
894:
888:
882:
875:
867:
861:
855:
837:
831:
824:
818:
812:
805:
799:
792:
786:
780:
776:
745:
741:
732:
728:
716:
712:
703:
699:
698:
692:
688:
686:
674:
670:
661:
657:
645:
641:
632:
628:
627:
620:
616:
612:
610:
598:
594:
585:
581:
576:
573:
572:
549:
545:
536:
532:
520:
516:
507:
503:
502:
496:
492:
490:
478:
474:
465:
461:
449:
445:
436:
432:
431:
425:
421:
419:
407:
403:
394:
390:
385:
382:
381:
377:
370:
363:
360:
353:
347:
343:
336:
329:
322:
315:
312:
305:
299:
280:
273:
267:
264:
257:
251:
247:
244:
237:
231:
227:
223:
216:
208:line of centers
199:
167:
150:
146:
114:(also called a
99:
86:
75:
69:
66:
56:Please help to
55:
39:
35:
28:
23:
22:
15:
12:
11:
5:
3409:
3399:
3398:
3393:
3388:
3373:
3372:
3337:
3327:
3324:
3323:
3301:
3300:
3298:
3295:
3293:
3292:
3287:
3285:radical center
3278:
3273:
3268:
3262:
3260:
3257:
3240:
3233:
3219:
3212:
3195:
3188:
3155:
3148:
3141:
3134:
3130:
3112:
3108:
3102:
3098:
3092:
3086:
3082:
3077:
3074:
3068:
3062:
3058:
3053:
3050:
3044:
3025:
3017:
3004:
3000:
2996:
2964:
2961:
2940:
2935:
2930:
2927:
2923:
2917:
2912:
2908:
2905:
2899:
2894:
2889:
2886:
2882:
2876:
2871:
2867:
2864:
2857:
2851:
2846:
2843:
2839:
2833:
2829:
2826:
2819:
2813:
2808:
2805:
2801:
2795:
2791:
2788:
2764:
2757:
2748:
2737:
2720:
2713:
2649:
2644:
2640:
2635:
2631:
2624:
2619:
2614:
2611:
2605:
2601:
2584:
2572:
2555:
2552:
2547:
2544:
2538:
2534:
2530:
2527:
2523:
2520:
2516:
2511:
2507:
2503:
2500:
2496:
2493:
2487:
2484:
2478:
2474:
2470:
2467:
2463:
2460:
2454:
2451:
2445:
2441:
2437:
2434:
2431:
2428:
2423:
2419:
2415:
2412:
2409:
2406:
2401:
2397:
2393:
2367:
2363:
2358:
2354:
2347:
2342:
2338:
2333:
2329:
2301:
2291:
2281:
2269:
2259:
2234:
2227:
2206:
2203:
2168:radical center
2162:
2155:
2148:
2141:
2134:
2127:
2110:
2107:
2095:
2090:
2085:
2082:
2078:
2072:
2067:
2063:
2060:
2054:
2049:
2044:
2041:
2037:
2031:
2026:
2022:
2019:
1992:
1987:
1982:
1979:
1975:
1969:
1964:
1960:
1957:
1951:
1946:
1941:
1938:
1934:
1928:
1923:
1919:
1916:
1896:, which means
1861:
1858:
1854:
1851:
1845:
1842:
1838:
1835:
1832:
1828:
1825:
1819:
1816:
1812:
1809:
1805:
1801:
1799:
1797:
1794:
1791:
1787:
1784:
1778:
1775:
1771:
1768:
1765:
1762:
1759:
1756:
1753:
1749:
1745:
1743:
1741:
1737:
1734:
1730:
1725:
1722:
1718:
1715:
1712:
1709:
1706:
1703:
1700:
1698:
1672:
1667:
1662:
1659:
1655:
1649:
1644:
1640:
1637:
1631:
1626:
1621:
1618:
1614:
1608:
1603:
1599:
1596:
1569:
1564:
1559:
1556:
1552:
1546:
1541:
1537:
1534:
1528:
1523:
1518:
1515:
1511:
1505:
1500:
1496:
1493:
1479:secant theorem
1462:
1457:
1453:
1449:
1446:
1443:
1440:
1437:
1432:
1428:
1424:
1420:
1417:
1411:
1408:
1404:
1401:
1398:
1394:
1391:
1387:
1384:
1381:
1354:
1351:
1348:
1343:
1339:
1335:
1331:
1328:
1324:
1321:
1318:
1280:
1276:
1273:
1267:
1264:
1260:
1257:
1254:
1250:
1247:
1241:
1238:
1234:
1231:
1207:
1204:
1201:
1197:
1194:
1188:
1185:
1181:
1178:
1175:
1172:
1169:
1166:
1163:
1139:
1133:
1128:
1125:
1121:
1115:
1111:
1108:
1101:
1095:
1090:
1087:
1083:
1077:
1073:
1070:
1062:
1058:
1055:
1051:
1046:
1043:
1039:
1036:
1033:
1030:
1027:
1024:
996:
993:
985:antihomologous
958:radical center
934:
931:
905:
899:
892:
886:
874:
871:
865:
859:
835:
829:
822:
816:
803:
797:
790:
784:
756:
753:
748:
744:
740:
735:
731:
727:
719:
715:
711:
706:
702:
695:
691:
685:
682:
677:
673:
669:
664:
660:
656:
648:
644:
640:
635:
631:
623:
619:
615:
609:
606:
601:
597:
593:
588:
584:
580:
560:
557:
552:
548:
544:
539:
535:
531:
523:
519:
515:
510:
506:
499:
495:
489:
486:
481:
477:
473:
468:
464:
460:
452:
448:
444:
439:
435:
428:
424:
418:
415:
410:
406:
402:
397:
393:
389:
375:
368:
358:
351:
341:
334:
327:
320:
310:
303:
278:
271:
262:
255:
242:
235:
215:
212:
198:
195:
166:
163:
88:
87:
42:
40:
33:
26:
9:
6:
4:
3:
2:
3408:
3397:
3394:
3392:
3389:
3387:
3384:
3383:
3381:
3370:
3366:
3362:
3358:
3354:
3350:
3343:
3338:
3334:
3329:
3328:
3319:
3315:
3314:
3306:
3302:
3291:
3288:
3286:
3282:
3279:
3277:
3274:
3272:
3269:
3267:
3264:
3263:
3256:
3254:
3250:
3245:
3239:
3232:
3226:
3218:
3211:
3202:
3194:
3187:
3181:
3177:
3173:
3165:
3161:
3110:
3106:
3100:
3096:
3090:
3080:
3075:
3072:
3066:
3056:
3051:
3048:
3042:
3031:we see that
3029:
3021:
3011:
2991:
2990:
2986:Consider the
2980:
2976:
2970:
2960:
2938:
2928:
2925:
2921:
2915:
2906:
2903:
2897:
2887:
2884:
2880:
2874:
2865:
2862:
2855:
2844:
2841:
2837:
2827:
2824:
2817:
2806:
2803:
2799:
2789:
2786:
2773:
2763:
2756:
2747:
2743:
2736:
2732:
2719:
2712:
2700:
2696:
2694:
2684:
2676:
2672:
2665:
2647:
2638:
2633:
2629:
2622:
2612:
2609:
2603:
2599:
2583:
2577:
2571:
2553:
2550:
2545:
2542:
2536:
2532:
2525:
2521:
2518:
2514:
2509:
2505:
2498:
2494:
2491:
2485:
2482:
2476:
2472:
2465:
2461:
2458:
2452:
2449:
2443:
2439:
2432:
2429:
2426:
2421:
2417:
2410:
2407:
2404:
2399:
2395:
2384:), therefore
2383:
2361:
2356:
2352:
2345:
2336:
2331:
2327:
2315:
2311:
2306:
2300:
2296:
2290:
2280:
2274:
2268:
2264:
2258:
2233:
2226:
2216:
2212:
2202:
2171:
2169:
2161:
2154:
2147:
2140:
2133:
2126:
2120:
2116:
2106:
2093:
2083:
2080:
2076:
2070:
2061:
2058:
2052:
2042:
2039:
2035:
2029:
2020:
2017:
1990:
1980:
1977:
1973:
1967:
1958:
1955:
1949:
1939:
1936:
1932:
1926:
1917:
1914:
1903:
1859:
1856:
1852:
1849:
1843:
1840:
1836:
1830:
1826:
1823:
1817:
1814:
1810:
1800:
1792:
1789:
1785:
1782:
1776:
1773:
1769:
1763:
1760:
1757:
1754:
1744:
1735:
1732:
1728:
1723:
1720:
1713:
1710:
1707:
1704:
1683:
1670:
1660:
1657:
1653:
1647:
1638:
1635:
1629:
1619:
1616:
1612:
1606:
1597:
1594:
1567:
1557:
1554:
1550:
1544:
1535:
1532:
1526:
1516:
1513:
1509:
1503:
1494:
1491:
1480:
1476:
1460:
1455:
1451:
1447:
1444:
1441:
1438:
1435:
1430:
1426:
1422:
1418:
1415:
1409:
1406:
1402:
1396:
1392:
1389:
1385:
1382:
1368:
1367:quadrilateral
1352:
1349:
1346:
1341:
1337:
1333:
1329:
1326:
1322:
1319:
1307:
1301:
1300:supplementary
1296:
1278:
1274:
1271:
1265:
1262:
1258:
1252:
1248:
1245:
1239:
1236:
1232:
1221:
1205:
1202:
1199:
1195:
1192:
1186:
1183:
1179:
1173:
1170:
1167:
1164:
1137:
1126:
1123:
1119:
1109:
1106:
1099:
1088:
1085:
1081:
1071:
1068:
1060:
1056:
1053:
1049:
1044:
1041:
1034:
1031:
1028:
1025:
1011:
1007:
1000:
992:
991:in Figure 4.
986:
982:
974:
966:
959:
946:
940:
930:
926:
922:
919:
915:
912:
904:
898:
891:
885:
880:
873:Special cases
870:
864:
858:
853:
849:
844:
842:
834:
828:
821:
815:
810:
802:
796:
789:
783:
774:
769:
754:
746:
742:
738:
733:
729:
717:
713:
709:
704:
700:
693:
689:
683:
675:
671:
667:
662:
658:
646:
642:
638:
633:
629:
621:
617:
613:
607:
599:
595:
591:
586:
582:
558:
550:
546:
542:
537:
533:
521:
517:
513:
508:
504:
497:
493:
487:
479:
475:
471:
466:
462:
450:
446:
442:
437:
433:
426:
422:
416:
408:
404:
400:
395:
391:
374:
367:
357:
350:
340:
333:
326:
319:
309:
302:
297:
293:
289:
277:
270:
261:
254:
241:
234:
220:
211:
209:
205:
194:
192:
187:
185:
180:
171:
158:
154:
143:
139:
137:
133:
129:
125:
121:
117:
113:
109:
96:
92:
84:
81:
73:
63:
59:
53:
52:
46:
41:
32:
31:
19:
3355:(1): 34–46,
3352:
3348:
3332:
3312:
3305:
3281:Radical axis
3246:
3237:
3230:
3224:
3216:
3209:
3206:
3200:
3192:
3185:
3174:
3170:
3023:
3015:
3008:. Since the
2987:
2985:
2972:
2774:
2761:
2754:
2745:
2741:
2734:
2730:
2717:
2710:
2705:
2692:
2689:
2666:
2588:and radius
2581:
2575:
2569:
2304:
2298:
2294:
2288:
2278:
2272:
2266:
2262:
2256:
2238:(Figure 5).
2231:
2224:
2221:
2208:
2172:
2159:
2152:
2145:
2138:
2131:
2124:
2115:radical axis
2112:
1898:R, P, S', Q'
1684:
1305:
1294:
1009:
1005:
1001:
998:
984:
980:
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380:, this is:
62:introducing
3380:Categories
3297:References
2967:See also:
2003:Similarly
973:homologous
184:projection
45:references
3369:122408307
3318:MathWorld
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70:May 2024
3391:Circles
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